Another seemingly straight-forward (children’s) math problem is making the rounds on the Internet. This time, it features fruit: apples, bananas, and coconuts. Now, the answer seems obvious at first glance, but due to a little (intentional?) visual trickery, the answer isn’t clear cut.

## Here’s the puzzle:

## Figure it out? Here’s the solution (s)…

The top equation shows 3 apples summing to 30, therefore we can conclude that each apple is worth 10.

The second equation shows 1 apples plus two equal bunches of bananas summing to 18. So now we can conclude that the bunches of bananas are worth 4 each. 10 + 4 + 4 = 18. Easy.

The third equation shows a bunch of bananas minus two coconut halves with equaling 2. We know the bunch of bananas is worth 4, so the 2 coconut halves must be worth 2, since 4 – 2 = 2.

In the final equation, we have one coconut half plus one apple plus one bunch of bananas. So, what’s the answer?

**Here’s where the debate begins…**

Some believe that if a pair of coconut halves equals two, then a single coconut half must equal one. Likewise, they believe that if a bundle of four bananas equals four, then a bundle of three must equal three, leaving a final answer of **14**. *As a side note, on first glance, I didn’t even notice that the bunch of bananas had 3 instead of 4 bananas…*

Others believe that the coconut image always equals two, while the bundle of bananas image always equals four, regardless of changes in the images. By this logic, the answer is **16**.

## So which is it?

14

note: i did not initially notice that the last bunch of bananas had three, either. and i say 14.