Does 0.999 (repeated) equal “one”? You might be surprised by the answer… which is “yes“. I heard this on a couple of podcasts over the last few months, and I still find it hard to accept at face value. However, I am now convinced and here’s several simple proofs that .99999 does indeed equal 1…

Does 0.999 (repeated) equal “one”? You might be surprised by the answer… which is “yes“. I heard this on a couple of podcasts over the last few months, and I still find it hard to accept at face value. However, I am now convinced and here’s several simple proofs that .99999 does indeed equal 1…

## Method 1:

Let x = **0.9999…**

Then 10x =** 9.9999…**

If we then subtract **x** from both sides of the equation, then:

**10x – x = 9.9999… – 0.9999…**

So, **9x = 9**

Divide both sides of the equation by 9, and…

**x = 1** … which, when we started, we said = 0.9999…

## Method 2:

**1/9 = 0.11111…**

Multiply both sides of the equation by 9:

**9 X 1/9 = 9 X 0.11111…**

**1 = 0.99999…**

## Method 3:

We know that 0.9 is not equal to 1; neither is 0.999, nor 0.99999. If you stop the expansion of 9s at any finite point, the fraction you have (like .99999 = 99999/100000) is never equal to 1. But each time you add a 9, the margin error is smaller (with each 9, the error is actually ten times smaller).

You can show (using calculus or other summations) that with a large enough number of 9s in the expansion, you can get arbitrarily close to 1. There is no other number that the sequence gets arbitrarily close to – it is always 1. Another way of saying this is that “the limit is 1?.

Thus, if you are going to assign a value to 0.9999…, the only sensible value is “1?.

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